Monday, September 6, 2010

Question 1

what is the  time taken by a 64kbps serial link to send a picture with 540 pixels?

18 comments:

  1. 540 pixels = 540 bytes
    speed of the link = 64kbps(b=bits)
    = 8KBps(B=bytes)
    hence time required = 540/8000
    = 67.5 secs (1min 7.5 secs)

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  2. The speed of the link given is 64kbps.This is same as 64/8=8 kile Bytes per second.So the time required to transfer would be 540/8000=67.5 secs which is approx 1 min 7.5 secs.

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  3. the time taken would be 1 minute 7.5 seconds

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  4. 540 pixels represent 540 bytes.So,we need to transmit 540 bytes.This is the same as 64/8=8 Kile Bytes per second (8 KBps).
    So the time required to transfer would be 540/8000=67.5 secs
    which is approx 1 min and 7.5 seconds

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  5. bytes.. Speed of link given is 64Kbps 64 Kilo bits per second .. This is the same as 64/8=8 Kile Bytes per second 8 KBpsNotice the capital B for bytes..So the time required to transfer would be 540 bytes..So, we need to transmit 540 bytes.. Speed of link given is 64Kbps 64 Kilo bits per second .. This is the same as 64/8=8 Kile Bytes per second 8 KBpsNotice the capital B for bytes.

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  6. it is approximately 67.5 seconds

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